6t^2-20t=-16

Solution for 6t^2-20t=-16 equation:

6t^2-20t=-16

We move all terms to the left:

6t^2-20t-(-16)=0

We add all the numbers together, and all the variables

6t^2-20t+16=0

a = 6; b = -20; c = +16;
Δ = b2-4ac
Δ = -202-4·6·16
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4}{2*6}=\frac{16}{12}
=1+1/3
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4}{2*6}=\frac{24}{12}
=2
$